Question

g Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution according to the equation H C 2 H 3 O 2 + N a O H ⟶ H 2 O + N a C 2 H 3 O 2 If you require 31.26 mL of 0.1871 M N a O H solution to titrate 10.0 mL of H C 2 H 3 O 2 solution, what is the concentration of acetic acid in the vinegar?

Answer 1

Answer: The concentration of acetic acid in the vinegar is 0.585 M

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $CH_3COOH$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1871M\\V_2=31.26mL$

Putting values in above equation, we get:

$1\times M_1\times 10.0=1\times 0.1871\times 31.26\\\\M_1=0.585M$

Thus the concentration of acetic acid in the vinegar is 0.585 M