Respuesta :

Answer:

[tex]Length=9\,\,units[/tex]

Step-by-step explanation:

Let, the length of the rectangle be 'L'

Width of the rectangle be 'W'

[tex]Width=Length-6\\\\W=L-6[/tex]

Area of the rectangle=[tex]27\,\,units[/tex]

Area of a rectangle= [tex]Length\times Width[/tex]

[tex]27=Length\times Width[/tex]

[tex]27=L\times (L-6)[/tex]

[tex]L^2-6L=27\\\\L^2-6L-27=0[/tex]

[tex]L^2+3L-9L-27=0\\\\ L(L+3)-9(L+3)=0\\\\(L+3)(L-9)=0\\\\[/tex]

Equating to zero:

[tex]L+3=0\\L=-3[/tex]

OR, Similarly:

[tex]L=9[/tex] units

The length of the rectangle cannot be negative,

therefore,

  [tex]Length=9\,\,units[/tex]

[tex]W=L-6\\\\W=9-6\\\\W=3\,\,units[/tex]

Answer:

9

Step-by-step explanation:

Have a good day :)

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