Respuesta :
Answer:
[tex]Length=9\,\,units[/tex]
Step-by-step explanation:
Let, the length of the rectangle be 'L'
Width of the rectangle be 'W'
[tex]Width=Length-6\\\\W=L-6[/tex]
Area of the rectangle=[tex]27\,\,units[/tex]
Area of a rectangle= [tex]Length\times Width[/tex]
[tex]27=Length\times Width[/tex]
[tex]27=L\times (L-6)[/tex]
[tex]L^2-6L=27\\\\L^2-6L-27=0[/tex]
[tex]L^2+3L-9L-27=0\\\\ L(L+3)-9(L+3)=0\\\\(L+3)(L-9)=0\\\\[/tex]
Equating to zero:
[tex]L+3=0\\L=-3[/tex]
OR, Similarly:
[tex]L=9[/tex] units
The length of the rectangle cannot be negative,
therefore,
[tex]Length=9\,\,units[/tex]
[tex]W=L-6\\\\W=9-6\\\\W=3\,\,units[/tex]