Question

Use scientific reasoning to explain what happens if 0.87 mol NaCl is dissolved in pure water creating 3.00 L of solution, what is its molarity of the resulting solution?

Answer 1

Answer : The molarity of the resulting solution is, 0.29 M

Explanation :

When NaCl dissolved in water then it dissociates to give sodium ions and chloride ions.

Given,

Moles of NaCl = 0.87 mol

Volume of solution = 3.00 L

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Moles of }NaCl}{\text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{0.87mol}{3.00L}=0.29mole/L=0.29M$

Therefore, the molarity of the resulting solution is, 0.29 M