Answer:
233.3N
Explanation:
Given:
radius 'r'= 1.5m
mass 'm'= 165kg
time 't'=2 sec
angular speed 'ω'= 0.6 rev/s
the magnitude of a torque is given by:
τ = F . r = I . α
where, 'α' is the angular acceleration and 'I' is the rotational inertia
F= I . α/ r =>[ ([tex]\frac{1}{2}[/tex] . m . [tex]r^{2}[/tex])(2π . ω/t) ]/r
F=[( [tex]\frac{1}{2}[/tex] . 165 . [tex]1.5^{2}[/tex])(2π . 0.6/2)]/1.5
F= 233.3N