Answer:
At the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.
Step-by-step explanation:
We are given that the mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of $2,000.
The ship building association wishes to find out whether their welders earn more or less than $20,000 annually.
Let [tex]\mu[/tex] = mean gross annual incomes of certified welders
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = $20,000
Alternate hypothesis, [tex]H_A[/tex] : [tex]\mu \neq[/tex] $20,000
Here, null hypothesis states that the mean income of welders is equal to $20,000.
On the other hand, alternate hypothesis states that the mean income of welders is not $20,000.
Also, the test statistics that would be used here is One-sample z test statistics as we know about the population standard deviation;
T.S. = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\bar X[/tex] = sample mean income
[tex]\sigma[/tex] = population standard deviation = $2,000
n = sample size
Now, at the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.