Question

does x^2-6x+3 have solutions that are real numbers

Answer 1

Answer:

X=10.8 and X=1.1

Step-by-step explanation:

Δ= b^2-4ac

= (-6)^2-4(1)(3)

=24

X1=

$\frac{6 + \sqrt{24} }{ {1}^{2} }$

=10.8

X2=

$\frac{6 - \sqrt{4} }{ {1}^{2} }$

=1.1