Question

A light bulb is connected to a 2V supply and experiences a current of 6.4A. What is the power rating of the bulb?

Answer 1

Answer:

12.8 Watts

Explanation:

P = VI

P = (2 V) (6.4 A)

P = 12.8 W

Answer 2

The power rating of the bulb will be 12.8 Watts. Power rating is an efficiency perameter.

What is the power rating?

The maximum power input allowed to pass through a piece of equipment is known as the equipment's power rating.

The given data in the problem is;

V is the voltage supply=  2V s

I is the current = 6.4A.

P is the power rating of the bulb =?

The power rating of the bulb is found as;

$\rm P = VI \\\\ \rm P = 2 \times 6.4 \\\\ \rm P =12.8 \ Watt$

Hence the power rating of the bulb will be 12.8 Watts.

To learn more about the power rating refer to the link;

https://brainly.com/question/13787703