Answer:
[tex]15\,\,kg/cm^2[/tex]
Step-by-step explanation:
Given:
The volume of a gas "V" varies inversely with the pressure "P" put on it.
Volume is 360 [tex]cm^3[/tex] under a pressure of 20 [tex]kg/cm^2[/tex]
To find:
pressure when volume is 480 [tex]cm^3[/tex]
Solution:
As of a gas "V" varies inversely with the pressure "P" put on it,
[tex]V=\frac{k}{P}[/tex]
Here, k is a constant
As volume is 360 [tex]cm^3[/tex] under a pressure of 20 [tex]kg/cm^2[/tex], put [tex]V=360\,,\,P=20[/tex]
[tex]360=\frac{k}{20}\\k=360\times 20\\=7200[/tex]
So,
[tex]V=\frac{7200}{P}[/tex]
Put [tex]V=480[/tex]
[tex]480=\frac{7200}{P}\\P=\frac{7200}{480}\\=15\,\,kg/cm^2[/tex]