Question

To prepare a solution of BF4-(aq), HF(g) is bubbled into a solution containing 50.0 g of H3BO3 in a 1 L reaction vessel. Calculate the maximum number of moles of BF4-(aq) that can be produced.

Answer 1

Answer:

Explanation:

The chemical reaction involved is as follows

H₃BO₃ + 4HF = HBF₄ + 3H₂O

1 mol                  1 mol

mol weight of H₃BO₃ is 61.84 gm

50g = 50 / 61.84 mol.

= 0.8 mol.

.8 mol of H₃BO₃ will form .8 mol of BF₄⁻ ion .