Answer:
2Li(s) + ⅛S₈(s, rhombic) + 2O₂(g) → Li₂SO₄(s)
Explanation:
A thermochemical equation must show the formation of 1 mol of a substance from its elements in their most stable state,.
The only equation that meets those conditions is the last one.
A and B are wrong , because they show Li₂SO₄ as a reactant, not a product.
C is wrong because Li⁺ and SO₄²⁻ are not elements.
D is wrong because it shows the formation of 8 mol of Li₂SO₄.
The thermochemical equation that illustrates ΔH°f for Li2SO4 is 2Li(s) + ⅛S₈(s, rhombic) + 2O₂(g) → Li₂SO₄(s)
A thermochemical equation refers to a stoichiometric chemical equation that is balanced and includes an enthalpy change ΔH.
It should be noted that the thermochemical equation must show the formation of 1 mole of a particular substance from its elements when the element is at its most stable state.
In this case, it should be noted that Li₂SO₄ is not a reactant, but rather a product. Therefore, the correct option is 2Li(s) + ⅛S₈(s, rhombic) + 2O₂(g) → Li₂SO₄(s)
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