I need help with this is khan academy

Answer:
y-intercept=32
Step-by-step explanation:
You can find the y-intercept using the slope-intercept form:
[tex]y=mx+b[/tex]
M is the slope and b is the y-intercept. To find the y-intercept, first find the slope. Take two of the points from the table (x,y) and use the slope formula:
[tex](64,12)(48,17)\\\\\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{rise}{run}[/tex]
Rise over run is the change in the y-axis over the change in the x-axis:
[tex](64(x_{1}),12(y_{1}))\\(48(x_{2}),17(y_{2}))[/tex]
[tex]\frac{17-12}{48-64}= \frac{5}{-16}=-\frac{5}{16}[/tex]
Now that we have the slope, insert into the equation:
[tex]y=-\frac{5}{16} x+b[/tex]
Take a point from the table and insert into the x and y values:
[tex](64_{x},12_{y})\\\\12=-\frac{5}{16}(64)+b[/tex]
Solve for b. Simplify parentheses:
[tex]-\frac{5}{16}*\frac{64}{1}=-\frac{320}{16}=-20[/tex]
[tex]12=-20+b[/tex]
Add 20 to both sides to isolate b:
[tex]20+12=-20+20+b\\32=b\\b=32[/tex]
If b equals 32, then the y-intercept is 32.**
Finito.
**The y-intercept is where x is equal to 0 (0,32)