Match its group with its percentage or mean using the table below.

Answer:
1) [tex]\bar x = 6.2[/tex], 2) [tex]\bar x = 8.75[/tex], 3) [tex]\bar x = 4.5[/tex], 4) [tex]p = 40\,\%[/tex], 5) [tex]p = 60\,\%[/tex], 6) [tex]p = 10\,\%[/tex]
Step-by-step explanation:
1) Mean length of all fish in the sample:
[tex]\bar x = \frac{12+5+3+5+8+2+10+9+4+4}{10}[/tex]
[tex]\bar x = 6.2[/tex]
2) Mean length of adult fish in the sample:
[tex]\bar x = \frac{12+5+8+10}{4}[/tex]
[tex]\bar x = 8.75[/tex]
3) Mean length of juvenile fish in the sample:
[tex]\bar x = \frac{5+3+2+9+4+4}{6}[/tex]
[tex]\bar x = 4.5[/tex]
4) Percentage of sample that were adult fish:
[tex]p = \frac{4}{10}\times 100\,\%[/tex]
[tex]p = 40\,\%[/tex]
5) Percentage of sample that were juvenile fish:
[tex]p = 100\,\% - 40\,\%[/tex]
[tex]p = 60\,\%[/tex]
6) Percentage of sample that were juveniles over 8 inches long:
[tex]p = \frac{1}{10}\times 100\,\%[/tex]
[tex]p = 10\,\%[/tex]