keiraly28
keiraly28 keiraly28
  • 30-04-2020
  • Mathematics
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Rafael spins the pointers of the two spinners shown at the right. Find the probability of each possible sum.

Rafael spins the pointers of the two spinners shown at the right Find the probability of each possible sum class=

Respuesta :

Newton9022 Newton9022
  • 07-05-2020

Answer:

P(sum 2)=1/6

P(sum 3)=1/3

P(sum 4)=1/3

P(sum 5)=1/6

Step-by-step explanation:

[tex]\left|\begin{array}{c|ccc}&1&2&3\\---&---&---&----\\1&2&3&4\\2&3&4&5\end{array}\right|[/tex]

On the table, there are a  a total of 6 outcomes.

  • Number of sum that equals 2=1
  • Number of sum that equals 3=2
  • Number of sum that equals 4=2
  • Number of sum that equals 5=1

Therefore:

P(sum 2)=1/6

P(sum 3)=2/6=1/3

P(sum 4)=2/6=1/3

P(sum 5)=1/6

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