Question

A 250g sample of water with an initial temperature of 98.8oC loses 1794 cal of heat. What is the final temperature of the water?

Answer 1

Answer:

91.62 C

Explanation:

Q  =  ( m ) ( Csh ) ( T2 - T1 )

T2  = T1  +  ( Q ) / ( m ) ( Csh )

T2  =  98.8 C  +  ( - 7500 J ) / ( 250 g ) ( 4.186 J/g - C )

T2  =  91.6 C