Question

What is the diameter of a circle with the equation (x + 6)2 + (y − 4)2 = 16?

Answer 1

Answer:

8 units

Step-by-step explanation:

${(x + 6)}^{2} + {(y - 4)}^{2} = 16 \\ {(x + 6)}^{2} + {(y - 4)}^{2} = {4}^{2} \\ equating \: it \: with \\ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\ {r}^{2} = {4}^{2} \implies \: r = 4 \\ d = 2r = 2 \times 4 = 8 \: units$

Hence, diameter of the circle is 8 units.