Respuesta :

Answer:

[tex] \red {\boxed{ \bold{ A= {x}^{2} + 10x + 24 }}}\\ [/tex]

Step-by-step explanation:

Length of rectangle (l) = (x + 6) units

Width of rectangle (w) =(x + 4) units

Let A represents the area of rectangle.

[tex]A= lw \\ = (x + 6)(x + 4) \\ = {x}^{2} + (6 + 4)x + 6 \times 4 \\ \purple {\boxed{ \bold{ A= {x}^{2} + 10x + 24 }}}\\ [/tex]

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