Answer:
q = 39
Step-by-step explanation:
[tex] {x}^{2} + 10x = 14 \\ {x}^{2} + 2.5.x = 14 \\ {x}^{2} + 10x + {5}^{2} = 14 + {5}^{2} \\ (x + 5)^{2} = 14 + 25 \\ {(x + 5)}^{2} = 39 \\ equating \: it \: with \\ (x + p) ^{2} = q \\ we \: find : \\ \huge \red{ \boxed{q = 39}}[/tex]
