Question

How much energy would need to be input to completely boil 17.3 moles of ice starting at 0 degrees * C and going to 100°C?

(H=40.5 kJ/mol ; H = 6.0kJ / (mol) ; specific

Answer 1

Answer:

$Q = 934.911\,kJ$

Explanation:

The energy needed to boil 17.3 moles of ice is:

$Q = (17.3\,mol)\cdot \left[\left(40.5\,\frac{kJ}{mol} \right)+ \left(\frac{4.186}{1000}\,\frac{kJ}{g\cdot ^{\circ}C} \right)\cdot \left(\frac{18.015\,g }{1\,mol} \right)\cdot (100^{\circ}C-0^{\circ}C)+\left(6\,\frac{kJ}{mol}\right)\right]$$Q = 934.911\,kJ$