Answer:
0.204 mol
Explanation:
Step 1: Write the balanced equation for the heating of calcium chloride dihydrate
CaCl₂.2H₂O ⇒ CaCl₂ + 2H₂O
Step 2: Calculate the moles of calcium chloride dihydrate
The molar mass of CaCl₂.2H₂O is 147.01 g/mol. The moles corresponding to 15.0 g of CaCl₂.2H₂O are:
[tex]15.0g \times \frac{1mol}{147.01g} = 0.102 mol[/tex]
Step 3: Establish the molar ratio of CaCl₂.2H₂O to H₂O
According to the balanced equation, the molar ratio of CaCl₂.2H₂O to H₂O is 1:2.
Step 4: Use the molar ratio to calculate the moles of water produced from 0.102 moles of calcium chloride dihydrate
[tex]0.102molCaCl_2.2H_2O \times \frac{2molH_2O}{1molCaCl_2.2H_2O} = 0.204molH_2O[/tex]
