Answer:
Considering the equation given:
[tex]y= 3x -2[/tex]
As a function:
[tex]f(x)= 3x -2[/tex]
[tex]$(2, -1)$[/tex] states for [tex](x, y)[/tex], which means, [tex]x=2[/tex] and [tex]y=-1[/tex]
[tex]f(2)= 3(2) -2\\f(2)= 6-2\\f(2)= 4[/tex]
[tex]4\neq -1[/tex]
Therefore, [tex]$(2, -1)$[/tex] is not a solution for the equation given and for the function.
