Question

Based on the records for the past several​ seasons, a sports fan believes the probability the red team wins is 0.45. The fan also believes the probability the blue team wins is 0.40. In a season with 180 ​games, how many more games should the fan expect the red team to​ win?

Answer 1

Answer:

9 more games

Step-by-step explanation:

180x.45=81 wins for the red team

180x.4=72 wins for the blue team

Answer 2

The fan can expect that the red team can win 9 more games.

Probability:

• It is a chance of any event to occur.
• It is given by: $P(E) = \frac{Favourable \ Outcomes}{Total \ Outcones}$
  

How to solve the given question?

• Total no of games in season = 180
• Probability of Red Team winning = 0.45 ⇒ No of Matches expected to win in the season = 0.45 × 180 = 81 Matches
• Probability of Blue Team winning = 0.4 ⇒ No of Matches expected to win in the season = 0.4 × 180 = 72 Matches
• Difference of matches expected to be won by Red and Blue Team = 81 -72 = 9 matches.

Thus, the red team is expected to win 9 matches more than the blue team.

Learn more about probability here:

https://brainly.com/question/251701

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