(A)Deren bought an iPhone that was on sale for $800. If he saved 30% and only payed 70% of the cost, what was the original price of the iPhone?
(B) How much money did he save?

Respuesta :

Answer:

A. The original cost of the phone was $1142.86

B. He saved $342.86

Step-by-step explanation:

To do this, we will use the percent equation, total*%=part. In this situation, the part is how much Deren paid for the phone, the percent is what percentage of the original cost of the phone he paid, and the part is what he actually paid.

total*% = part (original equation)

total * 0.7 = 800 (substitute known information)

Now, we then can solve for the total price using algebra.

total * 0.7 = 800 (original equation)

total * 0.7 / 0.7 = 800 / 0.7 (divide both sides by 0.7)

total = 1142.86 (divide)

Therefore the original cost of the iPhone was $1142.86

Next, we need to solve for the amount of money he saved, this is the difference between how much money he paid and how much the original price of the phone was.

total - cost = savings (original equation)

1142.86-800 = savings (substitute values)

342.86 = savings (subtract)

Therefore, he saved $342.86 off the cost of the iPhone.

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