Question

What is the Molarity of the Sulfate ion in a 2M K2SO4 solution?

Answer 1

Answer: The Molarity of the sulphate ion in a 2M  $K_2SO_4$ solution is 2M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute

$V_s$ = volume of solution in ml

$K_2SO_4\rightarrow 2K^{+}+SO_4^{2-}$

Now as 1 mole of $K_2SO_4$ gives = 1 mole of $SO_4^{2-}$

2 moles of $K_2SO_4$ gives =$\frac{1}{1}\times 2=2$ moles of $SO_4^{2-}$

Thus Molarity of the sulphate ion in a 2M $K_2SO_4$ solution is 2 M