Answer:
[tex]\large \boxed{\text{1.6 atm}}[/tex]
Explanation:
The only variables are the pressure and the volume, so we can use Boyle's Law.
Data:
p₁ = 2.0 atm; V₁ = 32 mL
p₂ = ?; V₂ = 40.0 mL
Calculation:
[tex]\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{2.0 atm} \times \text{32 mL} & = & p_{2} \times\text{40.0 mL}\\\text{64.0 atm} & = & 40.0p_{2}\\p_{2} & = & \dfrac{\text{64.0 atm}}{40.0}\\\\& = &\textbf{1.6 atm}\\\end{array}\\\text{The new pressure of the gas is $\large \boxed{\textbf{1.6 atm}}$}[/tex]
