The wavelength of a sound wave in this room is 1.13 m and the frequency is 301 Hz.
a. What is the speed of the wave in the room?

©Modeling Instruction Program 2004 3 W2, Mechanical Waves in 1D, WS 5 v3.2
b. If you double the frequency of the sound wave, determine its speed.

c. What happens to the wavelength if you cut the frequency in half? How do you know?
I'll throw in brainiest too.

Respuesta :

Answer:

a. 340.13 m/s b. 680.26 m/s c. our wavelength doubles

Explanation:

a. speed of wave, v = fλ were f = frequency = 301 Hz and λ = wavelength = 1.13 m.

v = fλ = 301 Hz × 1.13 m = 340.13 m/s

b. If we double the frequency then f = 2 × 301 Hz = 602 Hz

v = fλ = 602 Hz × 1.13 m = 680.26 m/s

c. If the speed of the wave is still 340.13 m/s, if we cut the frequency in half, then frequency now equals f = 301 Hz/2 = 150.5 Hz.

Since v = fλ,

λ = v/f = 340.13 m/s ÷ 150.5 Hz = 2.26 m.

Since our initial wavelength λ₀ = 1.13 m,

λ/λ₀ = 2.26 m/1.13 m = 2.

So, λ = 2λ₀ our wavelength doubles

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