Respuesta :
Answer:
22.7%
Explanation:
We must first put down the equation of reaction to guide our work while solving the problem.
KCN(aq) + HCl (aq)--> KCl(aq) + HCN(aq)
The questions specifically state that HCl is in excess so KCN is the limiting reactant.
Number of moles of KCN reacted= mass of KCN reacted / molar mass of KCN
Mass of KCN reacted= 3.2 g
Molar mass of KCN= 65.12 g/mol
Number of moles of KCN= 3.2/65.12 g/mol= 0.049 moles
Theoretical yield of HCN is obtained thus;
From the reaction equation;
1 mol of KCN produced 1 mole of HCN thus 0.049 moles of KCN will produce 0.049 moles of HCN.
Mass of HCN = number of moles ×molar mass
Molar mass of HCN= 27.0253 g/mol
Hence mass of HCN produced= 0.049mol × 27.0253 g/mol= 1.32g of HCN
Actual yield of HCN= 0.30g
% yield= actual yield/ theoretical yield ×100
% yield= 0.30/1.32 ×100
%yield= 22.7%
Answer:
The theoretical yield HCN is 1.33 grams
The percent yield HCN is 22.56 %
Explanation:
Step 1: Data given
Mass of KCN = 3.2 grams
Molar mass KCN = 65.12 g/mol
Mass of HCN produced = 0.30 grams
Step 2: The balanced equation
KCN + HCl --> KCl + HCN
Step 3: Calculate moles KCN
Moles KCN = mass KCN / moalr mass KCN
Moles KCN = 3.2 grams / 65.12 g/mol
Moles KCN = 0.0491 moles
Step 4: Calculate moles HCN
For 1 mol KCN we need 1 mol HCl to produce 1 mol KCl and 1 mol HCN
For 0.0491 moles HCN we'll have 0.0491 moles HCN
Step 5: Calculate mass HCN
Mass HCN = moles HCN * molar mass HCN
Mass HCN = 0.0491 moles * 27.03 g/mol
Mass HCN = 1.33 grams = the theoretical yield
Step 6: Calculate the percent yield HCN
Percent yield = (actual yiel / theoretical yield) * 100 %
Percent yield = (0.30 grams / 1.33 grams)
Percent yield = 22.56 %