Question

C(s)+ 1 /2 O 2 (g) CO(g) CO(g)+ 1 /2 O 2 (g) CO 2 (g) How will oxygen appear in the final chemical equation?

Answer 1

Answer : The oxygen will appears in the final chemical equation as a reactant.

Explanation :

The given chemical reactions are:

(1) $C(s)+\frac{1}{2}O_2(g)\rightarrow CO(g)$

(2) $CO(g)+\frac{1}{2}O_2(g)\rightarrow CO_2(g)$

Now we are adding reaction 1 and reaction 2, we get the final chemical equation.

The final chemical equation is:

$C(s)+O_2(g)\rightarrow CO_2(g)$

Thus, the oxygen will appears in the final chemical equation as a reactant.

Answer 2

Answer:

The oxygen will appears in the final chemical equation as a reactant.

Explanation:

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