Respuesta :
Answer:
The correct answer is 6.31 M
Explanation:
The molecular weight (MM) of NaOH is calculated as follows:
MM(NaOH) = Molar mass Na + Molar mass O + Molar mass H
= 23 g/mol + 16 g/mol + 1 g/mol
= 40 g/mol
We need the MM to convert from grams to moles. The molarity (moles of solute per liter of solution, in mol/L) can be calculated by dividing the mass into the volume in liters (195 ml = 0.195 L) and then multiplying by the MM as follows:
M = 49.24 g/0.195 L x 1 mol/40 g = 6.31 mol/L = 6.31 M
Answer:
M = 6.31 M
Explanation:
Data:
mass = 49.24 g of NaOH
solution volume = 195 mL = 0.195 L
MW NaOH = 39.99 g/mol
M = ?
The equation to calculate the molarity of a solution is as follows:
[tex]M=\frac{moles}{solution volume}[/tex]
To calculate the moles of NaOH the following equation is used:
[tex]MW=\frac{mass}{mol}[/tex]
Where MW is the molecular weight of NaOH, now we must clear the moles from the previous equation.
[tex]mol=\frac{mass}{MW}[/tex]
[tex]mol=\frac{49.24g}{39.99\frac{g}{mol} }=1.23 mol[/tex]
We place the moles and the volume of the solution in the molarity equation
[tex]M=\frac{1.23mol}{0.195L} =6.31 M[/tex]