Question

What is the potential energy of an apple that has a mass of 0.12 kg being
held 0.8 meters above the ground?

Answer 1

Answer:

$\displaystyle U_g = 0.9408 \ J$

General Formulas and Concepts:

Energy

Gravitational Potential Energy: $\displaystyle U_g = mgh$

• m is mass (in kg)
• g is gravity (9.8 m/s²)
• h is height (in m)

Explanation:

Step 1: Define

Identify variables

[Given] m = 0.12 kg

[Given] h = 0.8 m

[Solve] U

Step 2: Solve

1. Substitute in variables [Gravitational Potential Energy]:                                $\displaystyle U_g = (0.12 \ kg)(9.8 \ m/s^2)(0.8 \ m)$
2. Multiply:                                                                                                             $\displaystyle U_g = (1.176 \ kg \cdot m/s^2)(0.8 \ m)$
3. Multiply:                                                                                                             $\displaystyle U_g = 0.9408 \ J$

Topic: AP Physics 1 - Algebra Based

Unit: Energy

Book: College Physics