Answer:
[tex]4x\sqrt{26}[/tex].
Step-by-step explanation:
Given information:
[tex]Leg_1=4x[/tex]
[tex]Leg_2=20x[/tex]
According to the Pythagoras theorem,
[tex](hypotenuse)^2=(Leg_1)^2+(leg_2)^2[/tex]
Using Pythagoras theorem, we get
[tex](hypotenuse)^2=(4x)^2+(20x)^2[/tex]
[tex](hypotenuse)^2=16x^2+400x^2[/tex]
[tex](hypotenuse)^2=416x^2[/tex]
Taking square root on both sides.
[tex]hypotenuse=\sqrt{416x^2}[/tex]
[tex]hypotenuse=4x\sqrt{26}[/tex]
Hence, the expression of the hypotenuse is [tex]4x\sqrt{26}[/tex].
