Question

A rectangle has a height of t^2+7t+6t
2
+7t+6t, squared, plus, 7, t, plus, 6 and a width of 2t+12t+12, t, plus, 1.

Answer 1

Answer:

$2t^3+15t^2+19t+6$

Step-by-step explanation:

Height of the Rectangle$=t^2+7t+6$

Width of the Rectangle$=2t+1$

Area of the Rectangle = Height X Width

$=(2t+1)(t^2+7t+6)\\=2t(t^2+7t+6)+1(t^2+7t+6)\\=2t^3+14t^2+12t+t^2+7t+6\\ Collect like terms\\=2t^3+14t^2+t^2+12t+7t+6\\Area=2t^3+15t^2+19t+6$

The area of the rectangle is $2t^3+15t^2+19t+6$