A bag of marbles contains 4 red, 3 blue, 2 yellow, and 1 green marble. If
two marbles are drawn from the bag without replacement, the probability
that both marbles are red is: ​

Respuesta :

4 red, 3 blue, 2 yellow, and 1 green marble:

Gives total marbles of 10

First pick probability for any of our marbles:

Red: 4/10

Blue: 3/10

Yellow: 2/10

Green: 1/10

(4 + 3 + 2 + 1 = 10, which is our total, the marbles are over btw)

without replacement means it's (the marbles picked) not being put back after picking, so, total marbles drop down.

E.g. I have 5 orange, I take one without replacements. This means I must have 4 oranges in total now.

Second pick:

Lets say I get red, next pick:

probability is now over 9 due to no replacement:

Red: 3/9

Blue: 3/9

Yellow: 2/9

Green: 1/9

(3 + 3 + 2 + 1 = 9, which is our new total.)

So, total red drops down from 4 to 3, on our second pick. The rest remains the same due to not being picked

Thus, probability of picking the red red will be:

First pick x second pick

4/10 x 3/9 = 12/90

You don't need to simplify, if you do, you get the equivalent fraction of 2/15 for the probability.

Ans: 12/90 (or 2/15)

Hope this helps!

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