Respuesta :
Question:
1) The median weight for shelter A is greater than that for shelter B.
2)The median weight for shelter B is greater than that for shelter A.
3) The data for shelter A are a symmetric data set.
4) The data for shelter B are a symmetric data set.
5) The interquartile range of shelter A is greater than the interquartile range of shelter B.
Answer:
The correct options are;
1) The median for shelter A is greater than that for shelter B
4) The data for shelter B are a symmetric data set
5)The interquartile range for shelter A is greater than the interquartile range for shelter B
Step-by-step explanation:
Here we have weight of dogs in Shelter A
Min = 8
Max = 30
Lower interquartile = 17
Upper inter quartile = 28
Interquartile range = 28 - 17 = 9
Median = 21
For the dogs in shelter B
Min = 10
Max = 28
Lower interquartile = 16
Upper inter quartile = 20
Interquartile range = 20 - 16 = 4
Median = 18
Therefore, the median for shelter A is greater than that for shelter B
The data for shelter B are a symmetric data set
The interquartile range for shelter A is greater than the interquartile range for shelter B.
Answer:
Check below
Step-by-step explanation:
Hi there. I miss some data on the question, like the choices for instance.
But, let's focus on the Box plot and Whiskers, then.
1. Plotting the data, since the data is organized.
2. Separating the Lowest and the biggest value
Lowest value: 6
Biggest value: 28
Calculating the quartiles, we have
6 8 10 12 14 16 | 18| 20 22 24 26 28
Q1=11.5
Q2= 17
Q3= 22.5
Q3-Q1=22.5-17=5.5 (Interquartile Range)

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