Question

In a basketball tournament, Team A scored 5 less than twice as many points as Team B. Team C scored 80 more points than Team B. The combined score for all three teams was 983 points. Let the variable b represent Team B's total points. The equation representing this scenario is (2b – 5) + b + (b + 80) = 983. Team B scored 227 total points.

Answer 1

Answer:

Team B scored 227 points.

Step-by-step explanation:

The expression that models this problem is

$(2b-5)+b+(b+80)=983$

To know the total points Team B scored, we just need to solve the expression for $b$

$2b-5+b+b+80=983\\4b=983-80+5\\4b=908\\b=\frac{908}{4} \\b=227$

Therefore, Team B scored 227 points.

Notice that the problem specifies each term of the expression.

"Team A scored 5 less than twice as many points as Team B": $2b-5$

"Team C scored 80 more points than Team B": $b+80$

"They combined score was 983 points": = 983.

With all this information, we defined the expression to find $b$

Answer 2

Answer:

c

Step-by-step explanation: