Answer:
(a){62,63,64,68,69}
(b){66}
Step-by-step explanation:
Given the set: {60,61,62,63,64,65,66,67,68,69}
Event X: {x|x is an even number}={60,62,64,66,68}
Event Y: {y|y is a multiple of 3}={60,63,66,69}
Event Z: {z|z is a multiple of 5}={60,65}
Part A
Outcomes that are in event X or in event Y but not in both events.
={62,63,64,68,69}
Part B
Outcomes that are in both events X and Y={60,66}
Therefore, Outcomes that are in both events X and Y but not in Z={66}