Respuesta :

Sarith

Know that quadrilaterals’ with 4 sides the degrees should all add up to 360

a. 110

(110+62+78= 250

360 - 250 = 110)

b. 66

(84+78+2b+b = 360

162+3b = 360

3b = 198

b = 66)

c. 83

For 5 sides the degrees should add up to 540)

(101+152+38+2c+c = 540

291+3c=540

3c = 249

c = 83)

d. 30

For 6 sides the degrees should add up to 720

(108+102+4d+4d+4d+5d = 720

210+17d= 720

17d = 510

d = 30)

As for the others I’ll label them 1, 2, and 3...

1. 60

(105+75+2b+b = 360

180+3b= 360

3b = 180

b = 60)

2. 78

(125+65+92+a = 360

282+a = 360

a = 78)

3. 80

(130+65+120+[2c-15]+c = 540

315+[2c-15]+c = 540

3c-15 = 225

3c = 240

c = 80

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