Answer:
[tex] {x}^{2} + \frac{1}{2} x + \frac{1}{8} = 2 + \frac{1}{8}[/tex]
Step-by-step explanation:
To complete the square, take the coefficient of the middle term, half it, and then square it.
Add the result to both sides of the equation, to keep it balanced.
In this case:
[tex] { (\frac{1}{2} \div 2)}^{2} = { (\frac{1}{4} )}^{2} = \frac{1}{8} [/tex]
