Question

How do the areas of the parallelograms compare? The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2. The area of parallelogram 1 is 2 square units greater than the area of parallelogram 2. The area of parallelogram 1 is equal to the area of parallelogram 2. The area of parallelogram 1 is 2 square units less than the area of parallelogram 2.

Answer 1

Answer:

A. the area of parallelogram 1 is 4 square units greater than the area of parallelogram 2

Step-by-step explanation:

got it right on ed

Answer 2

The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2. Then the correct option is A.

What is the area of the parallelogram?

The vertices of the parallelogram are (x₁, y₁), (x₂, y₂), (x₃, y₃), and (x₄, y₄).

Then the area of the parallelogram will be

Area = 1/2 [(x₁y₂ + x₂y₃ + x₃y₄ + x₄y₁) - (y₁x₂ + y₂x₃ + y₃x₄ + y₄x₁)]

(x₁, y₁) ⇒ (0, 2)

(x₂, y₂) ⇒ (2, 6)

(x₃, y₃) ⇒ (4, 6)

(x₄, y₄) ⇒ (4, 0)

Then the area of parallelogram 1 will be

A₁ = 1/2 [(0 x 6 + 2 x 6 + 4 x 0 + 4 x 2) – (2 x 2 + 6 x 4 + 6 x 4 + 0 x 0)]

A₁ = 16 square units

(x₁, y₁) ⇒ (2, 0)

(x₂, y₂) ⇒ (4, -6)

(x₃, y₃) ⇒ (2, -6)

(x₄, y₄) ⇒ (0, -2)

Then the area of parallelogram 2 will be

A₂ = 1/2 [(2 x -6 + 4 x -6 + 2 x -2 + 0 x 0) – (0 x 4 + -6 x 2 + -6 x 0 + -2 x 2)]

A₂ = 12 square units

The difference of area will be

A₁ - A₂ = 16 – 12

A₁ - A₂ = 4 square units

Then the correct option is A.

The complete question is attached below.

More about the area of the parallelograms link is given below.

https://brainly.com/question/9148769

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