Respuesta :
Answer:
The likelihood that a point chosen inside the square will also be inside the circle: 78.54%
Step-by-step explanation:
- Let x is the side of the suqare
=> the area of the square is: [tex]x^{2}[/tex]
- Let d is the diameter of the circle
=> the area of the circle : [tex]\frac{1}{4} d^{2}[/tex]π
However, d=x because of the square property
<=> the area of the circle : [tex]\frac{1}{4} x^{2}[/tex]π
The likelihood that a point chosen inside the square will also be inside the circle:
the area of the circle / the area of the square
= [tex]\frac{1}{4} x^{2}[/tex]π / [tex]x^{2}[/tex]
= [tex]\frac{1}{4}[/tex] π *100%
= 0.7854 * 100%
= 78.54%
Answer:
the answer is likely :)
Step-by-step explanation: