Answer:
Step-by-step explanation:
[tex]((\frac{3}{4}) ^{x}) ^{-4} \\=(\frac{3}{4} )^{-4x} \\=\frac{3^{-4x} }{4^{-4x} } \\=\frac{4^{4x}}{3^{4x}} \\=(\frac{4}{3}) ^{4x}[/tex]
Range:(0,∞)