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What is the area of a triangle whose sides measure 12 inches, 14 inches, and 18 inches?

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Respuesta :

Answer:

A = [tex]8\sqrt{110}[/tex] [tex]inches^{2}[/tex]

Step-by-step explanation:

In this question, we are tasked with calculating the area of a triangle given the length of its three sides

Mathematically, we can calculate this using the Heron's formula

For Heron's formula, A = [tex]\sqrt{S(S-A)(S-B)(S-C)}[/tex]

WHERE S = [tex]\frac{A+B+C}{2}[/tex]

we take the lengths of the triangle as A,B and C respectively as given

S = (12 + 14 + 18)/2 = 22

Plugging the values into the equation, we have;

A = [tex]\sqrt{22(22-12)(22-14)(22-18)}\\ \\\sqrt{22(10)(8)(4)} \\\\\sqrt{7040}[/tex]

A = [tex]8\sqrt{110}[/tex] [tex]inches^{2}[/tex]

Answer:

8*sqrt(110)

Step-by-step explanation:

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