The sum of three consecutive numbers is 84. Write and solve a math expression in terms of n for the smallest of the three numbers. Include parentheses.

Respuesta :

Answer:  Required expression :  [tex](n-1)+n+(n+1)=84[/tex]

Smallest number = 27

Step-by-step explanation:

Let the three consecutive number be n-1 , n , n+1 .

Since , the sum of three consecutive numbers is 84.

[tex]\Rightarrow\ (n-1)+n+(n+1)=84[/tex]

Remove parenthesis

[tex]n-1+n+n+1=84[/tex]

Simplify

[tex]3n=84[/tex]

Divide both sides by 3, we get

[tex]n=28[/tex]

That means the three consecutive numbers would be (28-1) , 28 , (28+1)

i.e. 27 , 28 , 29.

Hence, the smallest number is 27.

ACCESS MORE