Question

(Math: pentagonal numbers) A pentagonal number is defined as for and so on. So, the first few numbers are 1, 5, 12, 22, .... Write a function with the following header that returns a pentagonal number: def getPentagonalNumber(n): Write a test program that uses this function to display the first 100 pentagonal numbers with 10 numbers on each line

Answer 1

Answer:

from math import sqrt

def getPentagonalNumber(n):

   return int((3 * n * n - n) / 2)

for p in range(1, 100, 10):

   for x in range(p, p+10):

       print(getPentagonalNumber(x), end=" ")

   print()

Explanation:

The nth pentagonal number can be found by  $\frac{3n^{2} -n }{2}$

Create a function called getPentagonalNumber that takes one parameter, n and calculates the nth pentagon number using the formula

Create a nested for loop that iterates 100 times. Call the getPentagonalNumber function inside the loop to calculate the first 100 pentagonal number with 10 numbers on each line