Answer:
35meV
Explanation:
To find the average translational kinetic energy you use the followinf formula:
[tex]E_k=\frac{3}{2}k_BT[/tex]
K_B: Boltzman' constant = 1.38*10^-23 J/K
T: standard temperature = 273.15K
By replacing these values you obtain:
[tex]E_k=\frac{3}{2}(1.38*10^{-23}J/K)(273.15K)=5.65*10^{-21}J[/tex]
in eV you have:
5.65*10^-12(6.242*10^18eV)=0.035eV=35meV
Hence, the average translational energy is 35meV
