Answer:
167.2 g
Explanation:
Known
VC4H10 = 21.3
T = 0.00 C (convert to Kelvin: 273 K)
P = 1.00 atm
Unknown
m = ?g
1. Write the balanced chemical equation
1 C4H10 + 1O2 -----> 4 CO2 + 5 H2O
2. Find the volume ratio of Carbon Dioxide to Butane
1 C4H10 4 CO2 = 4 volumes CO2 / 1 volume C4H10
3. Multiply by the known volume of n (butane)
21.3 L C4H10 x 4 volumes CO2 / 1 volume C4H10 = 85.2 L C4H10
4. Use ideal gas law
PV = nRT solve for n ----> n = PV/RT
n= (1.00 atm) (85.2 L) / (0.0821 L atm/mol K) (273) = 3.80 mol CO2
5. Find molar mass of CO2
1 C x 12 + 2 O x 16 = 44.00
6. Multiply the ideal gas law solution (3.80) by molar mass CO2 (44.00)
3.80 mol CO2 x 44.00 g CO2
= 167.2 g CO2
