Question

Place a number in each box so that each equation is true and each equation has at least one negative number. Choose a number single-digit number starting with the positive number, negative number - not ZERO 2^_x2^_=2^0

Answer 1

Answer:

x=1, y=-1

Step-by-step explanation:

Given the equation: $2^{x}X2^{y}=2^0$

where x and y are the blank boxes.

We want to find

• A positive value of x
• A negative value of y

That makes the equation true.

If x=1, y=-1

$2^{1}X2^{-1}=2^0$

This can be confirmed using addition law of indices($a^x+a^y=a^{x+y}$)

$2^{1}X2^{-1}=2^{1+(-1)}=2^{1-1}=2^0$

• In general, any pair of a number and its negative value will satisfy the equality.