Answer:
[tex] P(z<-1.55)=0.0606[/tex]
Step-by-step explanation:
For this case we want to find this probability:
[tex] P(z<-1.55)[/tex]
Because they want the area to the left of the value. We need to remember that the normal standard distribution have a mean of 0 and a deviation of 1.
We can use the following excel code: =NORM.DIST(-1.55,0,1,TRUE)
And we got:
[tex] P(z<-1.55)=0.0606[/tex]
The other possibility is use the normal standard table and we got a similar result.