Answer:
28.13 m
Explanation:
Parameters given:
Initial speed of the car, u = 15 m/s
Acceleration of the car, a = -4 m/s ²
(The acceleration is negative because it is a deceleration)
We can find the distance traveled by the car by applying of the Newton's equations of motion:
v² = u² + 2 * a * s
Where v = final velocity of the car (0 m/s since the car comes to rest)
s = distance moved by the car
Therefore:
0² = 15² + (2 * -4 * s)
0 = 225 - 8s
=> s = 225/8
s = 28.13 m
The distance moved by the car before it comes to a stop is 28.13 m.
