Question

Select the correct answer.
What is the electric field experienced by a charged balloon if the charge on the balloon is 9.4 x 10 coulombs and the force it experiences is 8.2
* 10^-2 newtons?​

Answer 1

Answer:

8.37×10⁻⁴ N/C

Explanation:

Electric Field: This is the ratio of electrostatic force to electric charge. The S.I unit of electric field is N/C.

From the question, the expression for electric field is given as,

E = F/Q.......................... Equation 1

Where E = Electric Field, F = force experienced by the charged balloon, Q = Charge on the balloon.

Given: F = 8.2×10⁻² Newton, Q = 9.8×10 Coulombs = 98 Coulombs

Substitute these values into equation 1

E = 8.2×10⁻² /98

E = 8.37×10⁻⁴ N/C

Hence the Electric Field of the charged balloon =  8.37×10⁻⁴ N/C

Answer 2

Answer:

8.36*10^-4N/C

Explanation:

To find the electric field you use the following formula:

$F=qE\\\\E=\frac{F}{q}$

F: electric force = 8.2*10^-2 N

q: charge of the balloon = 9.4*10 C

By replacing F and q you obtain:

$E=\frac{8.2*10^{-2}N}{9.4*10}=8.36*10^{-4}\frac{N}{C}$

hence, the electric field is 8.36*10^-4N/C