Answer:
1 mol / cm³
Explanation:
Mass of solute = 90g
Volume of solvent = 500mL
1mL = 1cm³
500mL = 500cm³
Molarity = no. Of moles of solute / volume of solvent
No. Of moles of solute = mass / molarmass
Molar mass of glucose C₆H₁₂O₆ = [(12*6) + (1*12) + (16*6)]
Molar mass of glucose = (72 + 12 + 96) = 180g/mol
No. Of moles of glucose = 90 / 180 = 0.5 moles
If 0.5 moles is present in 500cm³
X moles will be present in 1000cm³
= (1000 * 0.5) / 500
= 1 mol/cm³
The molarity of glucose is 1 mol/cm³
